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Simplifying b3 + 14b2 + 24b = 0 Reorder the terms: 24b + 14b2 + b3 = 0 Solving 24b + 14b2 + b3 = 0 Solving for variable 'b'. Factor out the Greatest Common Factor (GCF), 'b'. b(24 + 14b + b2) = 0 Factor a trinomial. b((12 + b)(2 + b)) = 0Subproblem 1
Set the factor 'b' equal to zero and attempt to solve: Simplifying b = 0 Solving b = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b = 0Subproblem 2
Set the factor '(12 + b)' equal to zero and attempt to solve: Simplifying 12 + b = 0 Solving 12 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + b = 0 + -12 Combine like terms: 12 + -12 = 0 0 + b = 0 + -12 b = 0 + -12 Combine like terms: 0 + -12 = -12 b = -12 Simplifying b = -12Subproblem 3
Set the factor '(2 + b)' equal to zero and attempt to solve: Simplifying 2 + b = 0 Solving 2 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + b = 0 + -2 b = 0 + -2 Combine like terms: 0 + -2 = -2 b = -2 Simplifying b = -2Solution
b = {0, -12, -2}
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